Area and depth determine volume
For a rectangular layer, volume in cubic feet = length in feet × width in feet × depth in inches / 12. Divide cubic feet by 27 for cubic yards. Measure separate runs at their actual depths instead of applying the deepest section to the entire site.
The gravel tool multiplies your entered geometric depth by area. It does not predict settlement or compaction and has no separate waste-percentage input. Clarify whether measurements describe loose material or a compacted target, then obtain the required delivered-depth or reserve assumption from the installer. A concrete layer on the same area needs its own thickness and material order.
Volume and weight use different units
Weight = cubic yards × density in U.S. short tons per cubic yard. Conversely, cubic yards per short ton = 1 / density. At 1.4 short tons/yd³, one short ton corresponds to about 0.714 yd³; at 1.6 it corresponds to 0.625. These are density scenarios, not fixed conversion rules for every gravel.
A U.S. short ton is 2,000 lb, or 907.18474 kg. A metric tonne is 1,000 kg. Convert short tons to tonnes by multiplying by 0.90718474. One cubic yard is about 0.764555 m³, so convert a short-ton/yd³ density to t/m³ by multiplying by 0.90718474 and dividing by 0.764555. Confirm actual bulk density, grading and moisture with the supplier.
Keep the estimated weight separate from the order
The tool’s order suggestion rounds upward to a half-unit increment in the selected weight system. A supplier may instead use a minimum load, scale-weight invoice or a different increment. Use the estimated weight to discuss an order rather than treating the interface’s rounding rule as the supplier’s contract.
Ask whether a quote is by volume or weight, and which ton definition appears on the invoice. Confirm access, unloading and any separately estimated material reserve. Changing the display from imperial to metric should convert the same physical weight; it should not merely relabel the same number as tonnes.
Convert the same layer in both weight systems
A 30 × 10 ft area at 4 in depth has 100 cu ft, or 100 / 27 = 3.7037 yd³. At an illustrative 1.4 U.S. short tons/yd³, estimated weight is 5.1852 short tons. Converted to metric it is about 4.704 tonnes, representing the same physical material before ordering increments.
Rounding the estimate up in half-unit steps produces 5.5 short tons or 5.0 metric tonnes, respectively. Those rounded orders are not identical physical weights; they follow different package increments. Increasing depth to 8 in doubles unrounded volume and weight when area and density stay the same. Confirm actual delivered density and compaction assumptions rather than using this example as a structural design.
Test your scenario
Use the related calculators
The guide frames the comparison; the calculators let you enter your own numbers and test alternatives.